Java Examples - Multiple Exceptions (Array out of bound)
Problem Description:
How to handle multiple exceptions while array is out of bound?
Solution:
This example shows how to handle multiple exception methods by using System.err.println() method of System class .
public class Main {
public static void main (String args[]) {
int array[]={20,20,40};
int num1=15,num2=10;
int result=10;
try {
result = num1/num2;
System.out.println("The result is" +result);
for(int i =5;i >=0; i--) {
System.out.println
("The value of array is" +array[i]);
}
}
catch (ArrayIndexOutOfBoundsException e) {
System.out.println("Array is out of Bounds"+e);
}
catch (ArithmeticException e) {
System.out.println ("Can't divide by Zero"+e);
}
}
}
Result:
The above code sample will produce the following result.
The result is1
Array is out of Boundsjava.lang.ArrayIndexOutOfBoundsException
: 5